Distance from Aleksandrow Lodzki to Wausau
The shortest distance (air line) between Aleksandrow Lodzki and Wausau is 4,531.11 mi (7,292.12 km).
How far is Aleksandrow Lodzki from Wausau
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:18 (10.01.2026)
Wausau is located in Wisconsin, United States within 44° 57' 43.2" N -90° 21' 14.76" W (44.9620, -89.6459) coordinates. The local time in Wausau is 11:18 (10.01.2026)
The calculated flying distance from Wausau to Wausau is 4,531.11 miles which is equal to 7,292.12 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Wausau, Wisconsin, United States