Distance from Aleksandrow Lodzki to Wilmington
The shortest distance (air line) between Aleksandrow Lodzki and Wilmington is 4,684.01 mi (7,538.18 km).
How far is Aleksandrow Lodzki from Wilmington
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:31 (14.01.2026)
Wilmington is located in North Carolina, United States within 34° 12' 35.64" N -78° 6' 48.24" W (34.2099, -77.8866) coordinates. The local time in Wilmington is 21:31 (13.01.2026)
The calculated flying distance from Wilmington to Wilmington is 4,684.01 miles which is equal to 7,538.18 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Wilmington, North Carolina, United States