Distance from Aleksandrow Lodzki to Woonsocket
The shortest distance (air line) between Aleksandrow Lodzki and Woonsocket is 4,055.63 mi (6,526.90 km).
How far is Aleksandrow Lodzki from Woonsocket
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 07:36 (12.01.2026)
Woonsocket is located in Rhode Island, United States within 42° 0' 3.6" N -72° 30' 2.52" W (42.0010, -71.4993) coordinates. The local time in Woonsocket is 01:36 (12.01.2026)
The calculated flying distance from Woonsocket to Woonsocket is 4,055.63 miles which is equal to 6,526.90 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Woonsocket, Rhode Island, United States