Distance from Aleksandrow Lodzki to Yazoo City
The shortest distance (air line) between Aleksandrow Lodzki and Yazoo City is 5,212.35 mi (8,388.47 km).
How far is Aleksandrow Lodzki from Yazoo City
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 13:49 (14.01.2026)
Yazoo City is located in Mississippi, United States within 32° 51' 42.84" N -91° 35' 33" W (32.8619, -90.4075) coordinates. The local time in Yazoo City is 06:49 (14.01.2026)
The calculated flying distance from Yazoo City to Yazoo City is 5,212.35 miles which is equal to 8,388.47 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Yazoo City, Mississippi, United States