Distance from Alexander City to Bad Sooden-Allendorf
The shortest distance (air line) between Alexander City and Bad Sooden-Allendorf is 4,718.29 mi (7,593.35 km).
How far is Alexander City from Bad Sooden-Allendorf
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 04:37 (15.01.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 11:37 (15.01.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 4,718.29 miles which is equal to 7,593.35 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany