Distance from Alexander City to Buggenhout
The shortest distance (air line) between Alexander City and Buggenhout is 4,497.54 mi (7,238.10 km).
How far is Alexander City from Buggenhout
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 03:38 (29.12.2024)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 10:38 (29.12.2024)
The calculated flying distance from Buggenhout to Buggenhout is 4,497.54 miles which is equal to 7,238.10 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Buggenhout, Arr. Dendermonde, Belgium