Distance from Alexander City to Civita Castellana
The shortest distance (air line) between Alexander City and Civita Castellana is 5,112.89 mi (8,228.40 km).
How far is Alexander City from Civita Castellana
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 17:53 (08.02.2025)
Civita Castellana is located in Viterbo, Italy within 42° 17' 45.96" N 12° 24' 36" E (42.2961, 12.4100) coordinates. The local time in Civita Castellana is 00:53 (09.02.2025)
The calculated flying distance from Civita Castellana to Civita Castellana is 5,112.89 miles which is equal to 8,228.40 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Civita Castellana, Viterbo, Italy