Distance from Alexander City to Civitanova Marche
The shortest distance (air line) between Alexander City and Civitanova Marche is 5,135.51 mi (8,264.80 km).
How far is Alexander City from Civitanova Marche
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 21:11 (12.02.2025)
Civitanova Marche is located in Macerata, Italy within 43° 17' 60" N 13° 43' 59.88" E (43.3000, 13.7333) coordinates. The local time in Civitanova Marche is 04:11 (13.02.2025)
The calculated flying distance from Civitanova Marche to Civitanova Marche is 5,135.51 miles which is equal to 8,264.80 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Civitanova Marche, Macerata, Italy