Distance from Alexander City to Diekirch
The shortest distance (air line) between Alexander City and Diekirch is 4,607.46 mi (7,414.99 km).
How far is Alexander City from Diekirch
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 20:40 (23.02.2025)
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 03:40 (24.02.2025)
The calculated flying distance from Diekirch to Diekirch is 4,607.46 miles which is equal to 7,414.99 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Diekirch, Luxembourg, Luxembourg
Related Distances to Diekirch
| Cities | Distance |
|---|---|
| Vianden to Diekirch | 5.06 mi (8.14 km) |
| Mersch to Diekirch | 8.54 mi (13.75 km) |
| Wiltz to Diekirch | 12.05 mi (19.39 km) |
| Echternach to Diekirch | 12.43 mi (20.01 km) |
| Clervaux to Diekirch | 13.71 mi (22.07 km) |
| Redange-sur-Attert to Diekirch | 13.88 mi (22.33 km) |
| Capellen to Diekirch | 17.16 mi (27.62 km) |
| Luxembourg to Diekirch | 17.75 mi (28.57 km) |
| Grevenmacher to Diekirch | 18.15 mi (29.22 km) |
| Remich to Diekirch | 24.25 mi (39.03 km) |
| Differdange to Diekirch | 26.67 mi (42.93 km) |
| Dudelange to Diekirch | 26.79 mi (43.11 km) |
| Esch-sur-Alzette to Diekirch | 26.83 mi (43.18 km) |