Distance from Alexander City to Lyaskovets
The shortest distance (air line) between Alexander City and Lyaskovets is 5,641.47 mi (9,079.06 km).
How far is Alexander City from Lyaskovets
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 10:47 (09.01.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 18:47 (09.01.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 5,641.47 miles which is equal to 9,079.06 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Lyaskovets, Veliko Tarnovo, Bulgaria