Distance from Alexander City to Mercato San Severino
The shortest distance (air line) between Alexander City and Mercato San Severino is 5,271.21 mi (8,483.20 km).
How far is Alexander City from Mercato San Severino
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 13:39 (14.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 20:39 (14.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 5,271.21 miles which is equal to 8,483.20 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Mercato San Severino, Salerno, Italy