Distance from Alexander City to Novy Jicin
The shortest distance (air line) between Alexander City and Novy Jicin is 5,083.63 mi (8,181.32 km).
How far is Alexander City from Novy Jicin
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 06:55 (10.01.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 13:55 (10.01.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 5,083.63 miles which is equal to 8,181.32 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Novy Jicin, Moravskoslezský kraj, Czechia