Distance from Alexander City to Oisterwijk
The shortest distance (air line) between Alexander City and Oisterwijk is 4,522.07 mi (7,277.56 km).
How far is Alexander City from Oisterwijk
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 02:23 (25.02.2025)
Oisterwijk is located in Midden-Noord-Brabant, Netherlands within 51° 34' 59.88" N 5° 12' 0" E (51.5833, 5.2000) coordinates. The local time in Oisterwijk is 09:23 (25.02.2025)
The calculated flying distance from Oisterwijk to Oisterwijk is 4,522.07 miles which is equal to 7,277.56 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Oisterwijk, Midden-Noord-Brabant, Netherlands