Distance from Alexander City to Opglabbeek
The shortest distance (air line) between Alexander City and Opglabbeek is 4,551.66 mi (7,325.19 km).
How far is Alexander City from Opglabbeek
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:10 (07.01.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 12:10 (07.01.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,551.66 miles which is equal to 7,325.19 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Opglabbeek, Arr. Maaseik, Belgium