Distance from Alexander City to Oranienburg
The shortest distance (air line) between Alexander City and Oranienburg is 4,795.78 mi (7,718.07 km).
How far is Alexander City from Oranienburg
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 13:08 (29.01.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 20:08 (29.01.2025)
The calculated flying distance from Oranienburg to Oranienburg is 4,795.78 miles which is equal to 7,718.07 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Oranienburg, Oberhavel, Germany