Distance from Alexander City to San Cesareo
The shortest distance (air line) between Alexander City and San Cesareo is 5,146.91 mi (8,283.14 km).
How far is Alexander City from San Cesareo
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 16:55 (21.02.2025)
San Cesareo is located in Roma, Italy within 41° 49' 0.12" N 12° 48' 0" E (41.8167, 12.8000) coordinates. The local time in San Cesareo is 23:55 (21.02.2025)
The calculated flying distance from San Cesareo to San Cesareo is 5,146.91 miles which is equal to 8,283.14 km.
Alexander City, Alabama, United States