Distance from Alexander City to San Lazzaro di Savena
The shortest distance (air line) between Alexander City and San Lazzaro di Savena is 4,994.64 mi (8,038.10 km).
How far is Alexander City from San Lazzaro di Savena
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 04:21 (22.02.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 11:21 (22.02.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,994.64 miles which is equal to 8,038.10 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
San Lazzaro di Savena, Bologna, Italy