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      Distance from Alexander City to San Pancrazio Salentino

      The shortest distance (air line) between Alexander City and San Pancrazio Salentino is 5,420.17 mi (8,722.91 km).

      How far is Alexander City from San Pancrazio Salentino

      Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 04:42 (22.02.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 11:42 (22.02.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 5,420.17 miles which is equal to 8,722.91 km.

      Alexander City, Alabama, United States

      Related Distances from Alexander City

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      Alexander City to Portland (Oregon)2,126.00 mi (3,421.47 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino