Distance from Alexander City to San Severino Marche
The shortest distance (air line) between Alexander City and San Severino Marche is 5,113.92 mi (8,230.06 km).
How far is Alexander City from San Severino Marche
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 04:36 (22.02.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 11:36 (22.02.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 5,113.92 miles which is equal to 8,230.06 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
San Severino Marche, Macerata, Italy