Distance from Alexander City to San Vito dei Normanni
The shortest distance (air line) between Alexander City and San Vito dei Normanni is 5,405.35 mi (8,699.08 km).
How far is Alexander City from San Vito dei Normanni
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:46 (22.02.2025)
San Vito dei Normanni is located in Brindisi, Italy within 40° 39' 20.16" N 17° 42' 12.96" E (40.6556, 17.7036) coordinates. The local time in San Vito dei Normanni is 12:46 (22.02.2025)
The calculated flying distance from San Vito dei Normanni to San Vito dei Normanni is 5,405.35 miles which is equal to 8,699.08 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
San Vito dei Normanni, Brindisi, Italy