Distance from Alexander City to Sannicandro Garganico
The shortest distance (air line) between Alexander City and Sannicandro Garganico is 5,267.96 mi (8,477.96 km).
How far is Alexander City from Sannicandro Garganico
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:54 (22.02.2025)
Sannicandro Garganico is located in Foggia, Italy within 41° 49' 59.88" N 15° 34' 0.12" E (41.8333, 15.5667) coordinates. The local time in Sannicandro Garganico is 12:54 (22.02.2025)
The calculated flying distance from Sannicandro Garganico to Sannicandro Garganico is 5,267.96 miles which is equal to 8,477.96 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Sannicandro Garganico, Foggia, Italy