Distance from Alexander City to Sansepolcro
The shortest distance (air line) between Alexander City and Sansepolcro is 5,057.03 mi (8,138.51 km).
How far is Alexander City from Sansepolcro
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 06:01 (22.02.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 13:01 (22.02.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 5,057.03 miles which is equal to 8,138.51 km.
Alexander City, Alabama, United States