Distance from Alexander City to Sassenburg
The shortest distance (air line) between Alexander City and Sassenburg is 4,705.82 mi (7,573.28 km).
How far is Alexander City from Sassenburg
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 19:52 (30.01.2025)
Sassenburg is located in Gifhorn, Germany within 52° 31' 0.12" N 10° 37' 59.88" E (52.5167, 10.6333) coordinates. The local time in Sassenburg is 02:52 (31.01.2025)
The calculated flying distance from Sassenburg to Sassenburg is 4,705.82 miles which is equal to 7,573.28 km.
Alexander City, Alabama, United States