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      Distance from Alexander City to Sint-Genesius-Rode

      The shortest distance (air line) between Alexander City and Sint-Genesius-Rode is 4,510.15 mi (7,258.38 km).

      How far is Alexander City from Sint-Genesius-Rode

      Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:28 (08.01.2025)

      Sint-Genesius-Rode is located in Arr. Halle-Vilvoorde, Belgium within 50° 44' 42" N 4° 20' 47.04" E (50.7450, 4.3464) coordinates. The local time in Sint-Genesius-Rode is 12:28 (08.01.2025)

      The calculated flying distance from Sint-Genesius-Rode to Sint-Genesius-Rode is 4,510.15 miles which is equal to 7,258.38 km.

      Alexander City, Alabama, United States

      Related Distances from Alexander City

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      Sint-Genesius-Rode, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Genesius-Rode