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      Distance from Alexander City to Sint-Pieters-Leeuw

      The shortest distance (air line) between Alexander City and Sint-Pieters-Leeuw is 4,505.25 mi (7,250.49 km).

      How far is Alexander City from Sint-Pieters-Leeuw

      Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 05:31 (08.01.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 12:31 (08.01.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,505.25 miles which is equal to 7,250.49 km.

      Alexander City, Alabama, United States

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw