Distance from Alexander City to Steenokkerzeel
The shortest distance (air line) between Alexander City and Steenokkerzeel is 4,512.08 mi (7,261.50 km).
How far is Alexander City from Steenokkerzeel
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 08:51 (08.01.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 15:51 (08.01.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,512.08 miles which is equal to 7,261.50 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium