Distance from Alexander City to Sveti Ivan Zelina
The shortest distance (air line) between Alexander City and Sveti Ivan Zelina is 5,145.97 mi (8,281.64 km).
How far is Alexander City from Sveti Ivan Zelina
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 20:34 (09.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 03:34 (10.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,145.97 miles which is equal to 8,281.64 km.
Alexander City, Alabama, United States
Related Distances from Alexander City
Sveti Ivan Zelina, Zagrebačka županija, Croatia