Distance from Alexandria to Chateauneuf-les-Martigues
The shortest distance (air line) between Alexandria and Chateauneuf-les-Martigues is 1,006.20 mi (1,619.32 km).
How far is Alexandria from Chateauneuf-les-Martigues
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 12:12 (08.11.2024)
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 11:12 (08.11.2024)
The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 1,006.20 miles which is equal to 1,619.32 km.
Alexandria, Teleorman, Romania
Related Distances from Alexandria
Chateauneuf-les-Martigues, Bouches-du-Rhône, France