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      Distance from Alexandroupoli to Chateauneuf-les-Martigues

      The shortest distance (air line) between Alexandroupoli and Chateauneuf-les-Martigues is 1,072.51 mi (1,726.04 km).

      How far is Alexandroupoli from Chateauneuf-les-Martigues

      Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 00:34 (06.01.2026)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 23:34 (05.01.2026)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 1,072.51 miles which is equal to 1,726.04 km.

      Alexandroupoli, Evros, Greece

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues