Distance from Alpharetta to Bad Sassendorf
The shortest distance (air line) between Alpharetta and Bad Sassendorf is 4,515.51 mi (7,267.01 km).
How far is Alpharetta from Bad Sassendorf
Alpharetta is located in Georgia, United States within 34° 4' 13.44" N -85° 43' 34.32" W (34.0704, -84.2738) coordinates. The local time in Alpharetta is 06:50 (15.01.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 12:50 (15.01.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,515.51 miles which is equal to 7,267.01 km.
Alpharetta, Georgia, United States
Related Distances from Alpharetta
Bad Sassendorf, Soest, Germany