Distance from Altus to Aleksandrovac
The shortest distance (air line) between Altus and Aleksandrovac is 5,864.27 mi (9,437.63 km).
How far is Altus from Aleksandrovac
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 15:37 (26.02.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 22:37 (26.02.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,864.27 miles which is equal to 9,437.63 km.
Altus, Oklahoma, United States
Related Distances from Altus
Aleksandrovac, Rasinska oblast, Serbia