Distance from Altus to Aleksandrow Kujawski
The shortest distance (air line) between Altus and Aleksandrow Kujawski is 5,338.90 mi (8,592.12 km).
How far is Altus from Aleksandrow Kujawski
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 17:01 (23.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:01 (24.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,338.90 miles which is equal to 8,592.12 km.
Altus, Oklahoma, United States
Related Distances from Altus
Aleksandrow Kujawski, Włocławski, Poland