Distance from Altus to Celakovice
The shortest distance (air line) between Altus and Celakovice is 5,332.87 mi (8,582.43 km).
How far is Altus from Celakovice
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 07:45 (10.01.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 14:45 (10.01.2025)
The calculated flying distance from Celakovice to Celakovice is 5,332.87 miles which is equal to 8,582.43 km.
Altus, Oklahoma, United States
Related Distances from Altus
Celakovice, Středočeský kraj, Czechia