Distance from Altus to Cesky Tesin
The shortest distance (air line) between Altus and Cesky Tesin is 5,481.75 mi (8,822.02 km).
How far is Altus from Cesky Tesin
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 07:11 (10.01.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 14:11 (10.01.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 5,481.75 miles which is equal to 8,822.02 km.
Altus, Oklahoma, United States
Related Distances from Altus
Cesky Tesin, Moravskoslezský kraj, Czechia