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      Distance from Altus to Court-Saint-Etienne

      The shortest distance (air line) between Altus and Court-Saint-Etienne is 4,951.74 mi (7,969.06 km).

      How far is Altus from Court-Saint-Etienne

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 02:17 (01.01.2025)

      Court-Saint-Etienne is located in Arr. Nivelles, Belgium within 50° 37' 59.88" N 4° 34' 0.12" E (50.6333, 4.5667) coordinates. The local time in Court-Saint-Etienne is 09:17 (01.01.2025)

      The calculated flying distance from Court-Saint-Etienne to Court-Saint-Etienne is 4,951.74 miles which is equal to 7,969.06 km.

      Altus, Oklahoma, United States

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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
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      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
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      Court-Saint-Etienne, Arr. Nivelles, Belgium

      Related Distances to Court-Saint-Etienne