Distance from Altus to Diepenbeek
The shortest distance (air line) between Altus and Diepenbeek is 4,972.63 mi (8,002.68 km).
How far is Altus from Diepenbeek
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 20:51 (03.01.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 03:51 (04.01.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,972.63 miles which is equal to 8,002.68 km.
Altus, Oklahoma, United States
Related Distances from Altus
Diepenbeek, Arr. Hasselt, Belgium