Distance from Altus to Fontainebleau
The shortest distance (air line) between Altus and Fontainebleau is 4,963.55 mi (7,988.06 km).
How far is Altus from Fontainebleau
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 17:03 (11.01.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 00:03 (12.01.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 4,963.55 miles which is equal to 7,988.06 km.
Altus, Oklahoma, United States
Related Distances from Altus
Fontainebleau, Seine-et-Marne, France