Distance from Altus to Harderwijk
The shortest distance (air line) between Altus and Harderwijk is 4,925.38 mi (7,926.64 km).
How far is Altus from Harderwijk
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 05:14 (22.02.2025)
Harderwijk is located in Veluwe, Netherlands within 52° 21' 0" N 5° 37' 0.12" E (52.3500, 5.6167) coordinates. The local time in Harderwijk is 12:14 (22.02.2025)
The calculated flying distance from Harderwijk to Harderwijk is 4,925.38 miles which is equal to 7,926.64 km.
Altus, Oklahoma, United States
Related Distances from Altus
Harderwijk, Veluwe, Netherlands