Distance from Altus to Montceau-les-Mines
The shortest distance (air line) between Altus and Montceau-les-Mines is 5,094.21 mi (8,198.33 km).
How far is Altus from Montceau-les-Mines
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 09:27 (12.01.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 16:27 (12.01.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 5,094.21 miles which is equal to 8,198.33 km.
Altus, Oklahoma, United States
Related Distances from Altus
Montceau-les-Mines, Saône-et-Loire, France