Distance from Altus to Ozarow Mazowiecki
The shortest distance (air line) between Altus and Ozarow Mazowiecki is 5,434.87 mi (8,746.58 km).
How far is Altus from Ozarow Mazowiecki
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 18:05 (24.02.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 01:05 (25.02.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 5,434.87 miles which is equal to 8,746.58 km.
Altus, Oklahoma, United States
Related Distances from Altus
Ozarow Mazowiecki, Warszawski zachodni, Poland