Distance from Altus to Palma di Montechiaro
The shortest distance (air line) between Altus and Palma di Montechiaro is 5,873.67 mi (9,452.76 km).
How far is Altus from Palma di Montechiaro
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 02:47 (12.02.2025)
Palma di Montechiaro is located in Agrigento, Italy within 37° 11' 36.96" N 13° 45' 56.88" E (37.1936, 13.7658) coordinates. The local time in Palma di Montechiaro is 09:47 (12.02.2025)
The calculated flying distance from Palma di Montechiaro to Palma di Montechiaro is 5,873.67 miles which is equal to 9,452.76 km.
Altus, Oklahoma, United States
Related Distances from Altus
Palma di Montechiaro, Agrigento, Italy