Distance from Altus to Reguengos de Monsaraz
The shortest distance (air line) between Altus and Reguengos de Monsaraz is 4,872.74 mi (7,841.92 km).
How far is Altus from Reguengos de Monsaraz
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 18:29 (25.02.2025)
Reguengos de Monsaraz is located in Alentejo Central, Portugal within 38° 25' 0.12" N -8° 28' 0.12" W (38.4167, -7.5333) coordinates. The local time in Reguengos de Monsaraz is 00:29 (26.02.2025)
The calculated flying distance from Reguengos de Monsaraz to Reguengos de Monsaraz is 4,872.74 miles which is equal to 7,841.92 km.
Altus, Oklahoma, United States
Related Distances from Altus
Reguengos de Monsaraz, Alentejo Central, Portugal