Distance from Altus to Salvatierra de Mino
The shortest distance (air line) between Altus and Salvatierra de Mino is 4,707.21 mi (7,575.52 km).
How far is Altus from Salvatierra de Mino
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 11:22 (01.03.2025)
Salvatierra de Mino is located in Pontevedra, Spain within 42° 4' 59.88" N -9° 30' 0" W (42.0833, -8.5000) coordinates. The local time in Salvatierra de Mino is 18:22 (01.03.2025)
The calculated flying distance from Salvatierra de Mino to Salvatierra de Mino is 4,707.21 miles which is equal to 7,575.52 km.
Altus, Oklahoma, United States
Related Distances from Altus
Salvatierra de Mino, Pontevedra, Spain