Distance from Altus to San Andres de Llevaneras
The shortest distance (air line) between Altus and San Andres de Llevaneras is 5,211.47 mi (8,387.04 km).
How far is Altus from San Andres de Llevaneras
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 11:40 (01.03.2025)
San Andres de Llevaneras is located in Barcelona, Spain within 41° 34' 23.88" N 2° 28' 58.08" E (41.5733, 2.4828) coordinates. The local time in San Andres de Llevaneras is 18:40 (01.03.2025)
The calculated flying distance from San Andres de Llevaneras to San Andres de Llevaneras is 5,211.47 miles which is equal to 8,387.04 km.
Altus, Oklahoma, United States
Related Distances from Altus
San Andres de Llevaneras, Barcelona, Spain