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      Distance from Altus to San Baudilio de Llobregat

      The shortest distance (air line) between Altus and San Baudilio de Llobregat is 5,201.14 mi (8,370.43 km).

      How far is Altus from San Baudilio de Llobregat

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 11:29 (01.03.2025)

      San Baudilio de Llobregat is located in Barcelona, Spain within 41° 20' 44.88" N 2° 2' 30.12" E (41.3458, 2.0417) coordinates. The local time in San Baudilio de Llobregat is 18:29 (01.03.2025)

      The calculated flying distance from San Baudilio de Llobregat to San Baudilio de Llobregat is 5,201.14 miles which is equal to 8,370.43 km.

      Altus, Oklahoma, United States

      Related Distances from Altus

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      Altus to Tampa (Florida)1,094.51 mi (1,761.45 km)
      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
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      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
      Altus to New York (New York)1,443.51 mi (2,323.11 km)
      Altus to Queens (New York)1,450.68 mi (2,334.64 km)
      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
      Altus to Dallas (Texas)194.57 mi (313.14 km)
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      San Baudilio de Llobregat, Barcelona, Spain

      Related Distances to San Baudilio de Llobregat