Distance from Altus to San Giuseppe Vesuviano
The shortest distance (air line) between Altus and San Giuseppe Vesuviano is 5,739.79 mi (9,237.30 km).
How far is Altus from San Giuseppe Vesuviano
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 10:07 (12.02.2025)
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 17:07 (12.02.2025)
The calculated flying distance from San Giuseppe Vesuviano to San Giuseppe Vesuviano is 5,739.79 miles which is equal to 9,237.30 km.
Altus, Oklahoma, United States
Related Distances from Altus
San Giuseppe Vesuviano, Napoli, Italy