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      Distance from Altus to San Gregorio di Catania

      The shortest distance (air line) between Altus and San Gregorio di Catania is 5,912.81 mi (9,515.75 km).

      How far is Altus from San Gregorio di Catania

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 12:37 (14.02.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 19:37 (14.02.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 5,912.81 miles which is equal to 9,515.75 km.

      Altus, Oklahoma, United States

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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania