Distance from Altus to San Lazzaro di Savena
The shortest distance (air line) between Altus and San Lazzaro di Savena is 5,458.47 mi (8,784.56 km).
How far is Altus from San Lazzaro di Savena
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 12:43 (14.02.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 19:43 (14.02.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 5,458.47 miles which is equal to 8,784.56 km.
Altus, Oklahoma, United States
Related Distances from Altus
San Lazzaro di Savena, Bologna, Italy