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      Distance from Altus to San Pancrazio Salentino

      The shortest distance (air line) between Altus and San Pancrazio Salentino is 5,889.42 mi (9,478.10 km).

      How far is Altus from San Pancrazio Salentino

      Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 10:59 (12.02.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 17:59 (12.02.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 5,889.42 miles which is equal to 9,478.10 km.

      Altus, Oklahoma, United States

      Related Distances from Altus

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      Altus to San Diego (California)1,029.96 mi (1,657.56 km)
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      Altus to Los Angeles (California)1,088.13 mi (1,751.18 km)
      Altus to Tampa (Florida)1,094.51 mi (1,761.45 km)
      Altus to Washington (District of Columbia)1,264.47 mi (2,034.96 km)
      Altus to Baltimore (Maryland)1,289.18 mi (2,074.74 km)
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      Altus to Portland (Oregon)1,436.77 mi (2,312.26 km)
      Altus to Brooklyn (New York)1,441.78 mi (2,320.32 km)
      Altus to New York (New York)1,443.51 mi (2,323.11 km)
      Altus to Queens (New York)1,450.68 mi (2,334.64 km)
      Altus to Seattle (Washington)1,486.08 mi (2,391.62 km)
      Altus to Boston (Massachusetts)1,606.61 mi (2,585.58 km)
      Altus to Dallas (Texas)194.57 mi (313.14 km)
      Altus to Houston (Texas)406.95 mi (654.92 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino