Distance from Altus to San Severino Marche
The shortest distance (air line) between Altus and San Severino Marche is 5,581.13 mi (8,981.96 km).
How far is Altus from San Severino Marche
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 13:29 (14.02.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 20:29 (14.02.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 5,581.13 miles which is equal to 8,981.96 km.
Altus, Oklahoma, United States
Related Distances from Altus
San Severino Marche, Macerata, Italy